Home
Class 12
PHYSICS
In a head-on collision between and alpha...

In a head-on collision between and `alpha`-particle and a gold nucleus, the distance of closest approach is 4.13 fermi. Calculate the energy of the particle. (1 fermi `= 10^(-15) m`)

Promotional Banner

Similar Questions

Explore conceptually related problems

In a head on collision between an alpha particle and gold nucleus (Z=79), the distance of closest approach is 39.5 fermi. Calculate the energy of alpha -particle.

In a head on collision between an alpha particle and a gold nucleius (Z=79),the distnace of closet approach is 39.5 fermi.Calculate the enrgy of alpha particle.

In a head-on collision between an alpha -particle and a gold nucleus, the minimum distance of approach is 3.95 xx 10^(4)m . Calculate the energy of the alpha -particle.

In a head on collision between an alpha particle and gold nucleus, the minimum distance of approach is 4xx10^(-14)m . Calculate the energy of of alpha -particle. Take Z=79 for gold.

Calculate the energy of an alpha -particle whose distance of closest approach with the gold nucleus is 29.5 fermi.

In Rutherford experiment, for head-on collision of alpha particles with a gold nucleus, the impact parameter is