A body executes `SHM`, such that its velocity at the mean position is `1ms^(-1)` and acceleration at exterme position is `1.57 ms^(-2)`. Calculate the amplitude and the time period of oscillation.

Velocity at the mean position and acceleration at extreme position of a body in SHM are equal in magnitude. What will be the time period ?

A particle executing linear SHM has a maximum velocity of 40 cm ^(-1) and a maximum acceleration of 50 cms^(-2) . Find its amplitude and the period of oscillation.

A body executing SHM has a maximum velocity of 1ms^(-1) and a maximum acceleration of 4ms^(-1) . Its time period of oscillation is

A body is executing S.H.M. when its displacement from the mean position is 4 cm and 5 cm, the corresponding velocity of the body is 10 cm/s and 8 cm/s . Then the time period of oscillation of the body is

A body executing SHM makes 100 vibrations/min if the speed at the mean position is 15ms^(-1) , calculate its path length. What is its velocity when it is half way be tween its mean position and extreme position?

The kinetic energy of a particle, executing SHM, is 16 J when it is at its mean position. If the amplitude of oscillations is 25 cm, and the mass of the particle is 5.12 kg, the time period of its oscillation is………….