`CH_(3)COOH` के एक `0*001 mol L^(-1), विलयन की छलकता `3*905 xx 10^(-5) Scm^(-1)` है इसकी मोलर छलकता तथा वियोजन की मात्रा `( alpha )` का परिकलन कीजिय |
दिया गया है ----
`^_((H^(+)))^0=349*6 Scm^2 mol^(-1)` `^^_((CH_(3)COOH))^0=40*Scm^(2)mol^(-1)`

The conductivity of 0.001 mol L^(-1) solution of CH_(3)COOH is 3.905xx10^(-5)S cm^(-1) . Calculate its molar conductivity and degree of dissociation (alpha) . ("Given":lamda_((H^(+)))^(@)=349.65 S cm^(2)mol^(-1)andlamda^(@)(CH_(3)COO^(-))=40.9 D cm^(2)mol^(-1))

The conductivity of 0.001 " mol "L^(-1) solution of CH_(3)COOH is 4.95xx10^(-5)" S "cm^(-1) . Calculate its molar conductance and degree of dissociation (alpha). "Given" lambda_((H^(+)))^(@)=349.6" S "cm^(2)mol^(-1), lambda_((CH_(3)COO^(-)))^(@)=40.95 cm^(2)mol^(-1)

The conductivity of 0.001 "mol" L^(-1) solution of CH_(3)COOH " is " 3.905 xx 10^(-5) "S" cm^(-1) . Calculate its molar conductivity and degree of dissociation (alpha) . "Given" lambda^(@) (H^(+)) = 349.6 "S" cm^(2) "mol"^(-1) " and " lambda^(0) (CH_(3)COO^(-)) = 40.9 "S" cm^(2) "mol"^(-1) (b) Define electrochemical cell. What happens if external potential applied becomes greater than E_(cell)^(@) of electrochemical cell?

The conductivity of 0.001 mol solution of CH_(3)COOH is 3.905xx10^(-5)" S.cm"^(-1) . Calculate its molar conductivity and degree of dissociation (alpha) . ["Given: "lambda^(@)(H^(+))="349.6 S.cm"^(2)."mol"^(-1) and lambda^(@)(CH_(3)COO^(-))="40.9 S.cm"^(2)."mol"^(-1)]