The period of `cos(theta/2)`

The period of cos5 theta is

The period of cos5 theta is

The period of cos5 theta is

The period of cos5 theta is (a) pi^(2) (b) 2 pi (c) 2 pi/5 (d) pi/3

The period of sin^(2) theta , is

The period of sin^2theta is

If cos theta + (1)/(cos theta) = 4 , then prove that cos^(2) theta + (1)/(cos^(2)theta) = 14.

If sqrt(3)sin theta=cos theta, find the value of (3cos^(2)theta+2cos theta)/(3cos theta+2)

The solution of cos2theta=cos^(2)theta is:

The expression cos^(2)(theta+b)+cos^(2)(theta+a+b)+cos^(2)a-2cos a cos(theta+b).cos(theta+a+b) is independent of A) a B) b C) theta D) None of these