Compute the number of ordered quadruples of positive integers `(a,b,c,d)` such that `a!b!c!d!`=`24!`

The number of (a, b, c), where a, b, c are positive integers such that abc = 30, is

Let a,b.c.d,e,f be positive integers such that (a)/(b) =b+f

If a,b,c,d,e are five positive numbers, then

The number of pair of positive integers whose sum is 99 and HCF is 9 is (a) 5 (b) 4 (c) 3 (d) 2

If a,b,c,d, are first 4 positive odd integers then their sum is

If a,b,c and d are odd natural numbers such that a+b+c+d=20, the number of values of the ordered quadruplet (a,b,c,d) is