If `cos alpha+cos beta+cos gamma=sin alpha+sin beta+sin gamma=0`, and `cos(alpha-beta)+cos(beta-gamma)+cos(gamma-alpha)=6K`,`K in R`, then K is equal to :

If cos alpha + cos beta + cos gamma = 3 then sin alpha + sin beta + sin gamma =

If cos alpha+cos beta+cos gamma=0 and also sin alpha+sin beta+sin gamma=0 then prove that

If cos alpha + cos beta + cos gamma = 0 = sin alpha + sin beta + sin gamma then cos ^ (2) alpha + cos ^ (2) beta + cos ^ (2) gamma is

cos alpha+cos beta+cos gamma=0sin alpha+sin beta+sin gamma=0 then the value of sin^(4)alpha+sin^(4)beta+sin^(4)gamma

Let A and B denote the statements A : cos alpha + cos beta + cos gamma =0 B : sin alpha + siin beta + sin gamma = 0 If cos(beta - gamma) + cos (gamma -alpha) + cos (alpha -beta) = - (3)/(2) , then

Prove that cos alpha+cos beta+cos gamma+cos(alpha+beta+gamma)=4cos((alpha+beta)/(2))cos((beta+gamma)/(2))cos((gamma+alpha)/(2))

Prove that cos alpha+cos beta+cos gamma+cos(alpha+beta+gamma)=4cos((alpha+beta)/(2))cos((beta+gamma)/(2))cos((gamma+alpha)/(2))