The distances of a point 'P' from the points `A(5,-4),B(7,6)` are in the ratio `2:3` and the locus of P is `x^(2)+y^(2)-(34)/(5)x+(120)/(5)y+k=0` then "k" is

If the distance from P to the points (5,-4),(7,6) are in the ratio 2:3, then the locus of P is

If the distance from P to the points (5,-4),(7,6) are in the ratio 2:3, then the locus of P is

If the distances from P to the points (5,–4), (7, 6) are in the ratio 2 : 3, then find the locus of P

If the distances from P to the points (5,-4),(7,6) are in the ratio 2:3, then find the locus

If the distance from P to the points (5,-4),(7,6) are in the ratio 2:3 ,then the locus of P is 5x^(2)+5y^(2)-12x-86y+17=0 , 5x^(2)+5y^(2)-34x+120y+29=0, 5x^(2)+5y^(2)-5x+y+14=0 3x^(2)+3y^(2)-20x+38y+87=0

The distance of the point (-3,4) from the line 3x+4y-5=0 is (2)/(5) .

If A=(0,4),B=(0,-4) and |PA-PB|=6 and the locus of P is 7y^(2)-9x^(2)=9k ,Then k is

If the point P(k-1,2) is equidistant from the points A(3,k) and B(k,5), find the values of k

Find the distance of the point P from the line l in that : l:12(x+6)=5 (y-2) and P-=(-3, -4)