Home
Class 12
PHYSICS
Find the kinetic enegry of electrons emi...

Find the kinetic enegry of electrons emitting light in a medium with refractive index `n = 1.50` at an angle `theta = 30^(@)` to their propagation direction.

Promotional Banner

Similar Questions

Explore conceptually related problems

The speed of light in a medium of refractive index 1.5 is ________.

Find the lowest values o fthe kinetic energy of an electron and a proton causing the emergence of Cherenkov's radiation in a medium with refractive index n = 1.60 . For what particles is this minimum value of kinetic enegry equal to T_(min) = 29.6MeV ?

The wavelength of light in vacuum is lambda . The wavelength of light in a medium of refractive index n will be

If the wavelength of light in vacuum be lambda , the wavelength in a medium of refractive index n will be

If the wavelength of light in vacuum be lambda , the wavelength in a medium of refractive index n will be

What is the angle of incidence when light passes from vaccume to a medium of refractive index sqrt3 ? Angle of refraction is 30^@ . What is the angle of deviation in this case?

Find the conditions under which a charged particle moving uniformly through a medium with refractive index n emits light (the Vavilov-Cherenkov effect). Find also the direction of that radiations.

If the critical angle of the medium is sin^-1(3/5) Find the refractive index of the medium and polarising angle.

Light enters from vacuum to a medium of refractive index mu . If angle of incidence is double of angle of refraction, find angle of refraction.

A ray of light of wavelength 720 nm is refracted into a medium of refractive index 1.5. The wavelength of light in the medium is