The equation of a transverse wave travelling along a string is given by `y = 5 cos pi (100t - x)cm`. Its wavelength is

The equation of a transverse wave travelling along a string is given by y=0.4sin[pi(0.5x-200t)] where y and x are measured in cm and t in seconds. Suppose that you clamp the string at two points L cm apart and you observe a standing wave of the same wavelength as above transverse wave. For what values of L less than 10 cm is this possible?

The equation of a transverse wave travelling along a string is given by y=0.4sin[pi(0.5x-200t)] where y and x are measured in cm and t in seconds. Suppose that you clamp the string at two points L cm apart and you observe a standing wave of the same wavelength as above transverse wave. For what values of L less than 10 cm is this possible?

The equation of a transverse wave travelling in a rope is given by y = 5 sin (4t - 0.02 x) , where y and x are in cm and time t is in second. Then the maximum transverse speed of wave in the rope is

The equation of a transverse wave travelling on a rope is given by y =10 sin pi (0.01xx -2.00t) where y and x are in cm and t is in seconds. The maximum transverse speed of a particle in the rope is about

The equation of a wave travelling in a string can be written as y = 3 cos pi (10t-x) . Its wavelength is

The equation for the transverse wave travelling along a string is y = 4 sin 2pi ((t)/(0.05) -(x)/(60)) lengths expressed in cm and time period in sec. Calculate the wave velocity and maximum particle velocity.

The equation of a transverse wave travelling on a rope is given by y = 10sin pi (0.01x-2.000t) where y and x are in cm and t in seconds. The maximum transverse speed of a particle in the rope is about