ABCDE is a regular hexagon. i) If `bar(AB) + bar(AE)+ bar(BC) + bar(DC) + bar(ED) + bar(AC)=lambdabar(AC)` then `lambda=`

ABCDEF is a regular hexagon. If bar(AB)+bar(AE)+bar(BC)+bar(DC)+bar(ED)+bar(AC)=lambdabar(AC)" then "lambda=

ABCDEF is a regular hexagon. If bar(AB)=bar(a), bar(BC)=bar(b)" then "bar(CE)=

ABCDEF is a regular hexagon. If bar(AB)=bar(a), bar(BC)=bar(b)" then "bar(FA)=

If ABCDEF is a regular hexagon , then bar(AB) + bar(AC) + bar(AE) + bar(AF) =

If ABCDEF is a regular hexagon, then bar(AC) + bar(AD) + bar(EA) + bar(FA) =

If ABCDE is a pentagon, then bar(AB) + bar(AE) + bar(BC) + bar(DC) + bar(ED) =

ABCDEF is a regular hexagon. bar(AB)+bar(AC)+bar(AD)+bar(EA)+bar(FA)=

ABCDE is a pentagon. If the sum of the vectors bar(AB),bar(AE), bar(BC), bar(DC), bar(ED), bar(AC) is lambda bar(AC) then find the value of lambda .