For all real value of `theta` , `A=sin^2theta+cos^4theta`

A For all real value of theta,A=3cos^(2)theta+sin^(4)theta

Show that, for all real values of theta the function (2 sin theta+ cos theta)/(3 sin theta+ 4 cos theta) is increasing.

Given A=sin^2theta +cos^4theta . Then for all real values of theta , which one is correct ?

If (sin theta + cos theta)/(sin theta - cos theta)=3 , then the value of sin^(4)theta - cos^(4)theta is:

If 3tan theta=4, find the value of (4cos theta-sin theta)/(2cos theta+sin theta)

If 3cot theta=4, find the value of (4cos theta-sin theta)/(2cos theta+sin theta)

sin^(4) theta + cos ^(4) theta + 2sin^(2) theta cos ^(2) theta has value 1.

The value of cos^4theta+sin^4theta-6cos^2theta is (a) cos2theta (b) sin2theta (c) cos4theta (d) none of these