A lead bullet penetrates into a solid object and melts. Assuming that 50% of its kinetic energy was used to heat it, calculate the initial speed of the bullet. The initial temperature of the bullet is `27^@C` and its melting point is `327^@C`. Latent heat of fusion of lead `= 2.5 xx (10^4) J//kg` and specific heat capacity of lead `=125 J//kg-K`.

A lead bullet penetrates into a solid object and melts Assuming that 50% of its K.E. was used to heat it , calculate the initial speed of the bullet , The initial temp , of bullet is 27^(@)c and its melting point is 327^(@)C Latent heat of fasion of lead = 2.5 xx 10^(4) J kg^(-1) and sp heat capacity of lead = 1.25 J kg^(-1) K^(-1)

A lead bullet penetrates into a solid object and melts Assuming that 50% of its K.E. was used to heat it , calculate the initial speed of the bullet , The initial temp , of bullet is 27^(@)c and its melting point is 327^(@)C Latent heat of fasion of lead = 2.5 xx 10^(4) J kg^(-1) and sp heat capacity of lead = 125 J kg^(-1) K^(-1)

During the Indo-Pakistan war, a soldier observed that the lead bullet fired by him just melted, when stopped by an obstacle. Assuming that whole of the kinetic energy of bullet got converted into heat energy, calculate the velocity of the bullet. Given that initial temperature of the bullet = 47.6^(@)C . Melting point of lead 321^(@)C , specific heat of lead = 0.3 cal g^(-1).^(@)C^(-1) , latent heat of lead = 6 cal g^(-1) and J = 4.2 xx 10^(7) erg cal^(-1) .

A lead bullet of initial temperature 27^(@)C and speed 'V' kmph pnetrates into a solid object and melts. If 50% of the kinetic energy is used to heat it, the value of v in kmph is (for leads melting point=600K, latent heat of fusion =2.5xx10^(4)JKg^(-1), "specific heat" =125 J kg^(-1) k^(-1))

A lead bullet just melts when stopped by an obstacle. Assuming that 25 per cent of the heat is absorbed by the obstacle, find the velocity of the bullet if its initial temperature is 27^@C . (Melting point of lead = 327^@C , specific heat of lead =0.03 cal//g.^@C , latent heat of fusion of lead =6 cal//g, J = 4.2 J//cal ).

A lead bullet just melts when stopped by an obstacle. Assuming that 25 per cent of the heat is absorbed by the obstacle, find the velocity of the bullet if its initial temperature is 27^@C . (Melting point of lead = 327^@C , specific heat of lead =0.03 cal//g-^@C , latent heat of fusion of lead =6 cal//g, J = 4.2 J//cal ).

A lead bullet just melts when stopped by an obstacle. Assuming that 25% of heat is absrobed by the obstacle find the velocity of the bullet if the initial temperature was 27^(@)C. Melting point of lead = 327^(@)C, specific heat of lead =0.03 cal g ^(-1) ""^(@)C ^(-1). Latent heat of fusion of lead =6 cal g ^(-1).