A pendulum bob is swinging in a vertical plane such that its angular amplitude is less than `90^(@)`. At its highest point, the string is cut. Which trajectory is possible for the bob afterwards ?

A simple pendulum is swinging in vertical plane. The ratio of its potential energies when it is making angles 45^(@) and 90^(@) with the vertical is

A simple pendulum is swinging vertical plane. The ratio of its potential energy when it is making 45^(@) and 90^(@) with the vertical is

Identify wrong statements among the following The greater the mass of a pendulum bob, the shorter is its frequency of oscillation A simple pendulum with a bob of mass M swings with an angular amplitude of 40^(@) . When its angular amplitude is 20^(@) , the tension in the string is less than Mgcos 20^(@) . (3) The fractional change in the time period of a pendulum on changing the temperature is independent of the length of the pendulum. As the length of a simple pendulum is increased, the maximum velocity of its bob during its oscillation will also decreases.

A bob tied to the end of a string of length 2m, other end of which is fixed at a point in a vertical wall at a point O. The bob is imparted a vertical downward velocity of 5 m//s when the string is horizontal and swings in a vertical plane. Find the angular displacement of the bob from its initial position, when the string breaks. Given that the tensile strength of the string is twice the weight of the bob. Take g=10 m//s^(2)

A simple pendulum with a bob of mass 'm' swings with angular amplitude of 60^@ . When its angular displacement is 30^@ , the tension in the strings would be

A simple pendulum with a bob of mass m swings with an angular amplitude of 40^@ . When its angular displacement is 20^@ , the tension in the string is greater than mg cos 20^@

A simple pendulum with a bob of mass m swings with an angular amplitude of 40^@ . When its angular displacement is 20^@ , the tension in the string is greater than mg cos 20^@