If A(1,-1,3), B(2,1,-2), C(-5,2-6) are the vertices of a `triangleABC`, then the lengh of internal bisector of angle A is

If A(1, -1, -3), B(2, 1, -2), C(-5, 2, -6) are the vertices of a DeltaABC , then the length of internal bisector of angle A is

If A(3,1,-1),B(4,-1,1),C(5,2,1) be the vertices of a Delta ABC then the length of the internal bisector of angle A is

If A(5,-1),B(-1,7) and C(1,2) are the verticles of a triangle find the equation of the internal bisector of angleA

If A=(1, 1, 1), B=(1, 2, 3), C=(2, -1, 1) be the vertices of a DeltaABC , then the length of the internal bisector of the angle 'A' is

A (1,3) and C (-2/5,-2/5) are the vertices of a triangle ABC and the equation of the internal angle bisector of angleABC is x+y =2 Equation of BC is

A(1,3) and C(-2/5, -2/5) are the vertices of a triangle ABC and the equation of the internal angle bisector of angleABC " is " x+y=2. The coordinates of vertex B are

A(1,-1,-3),B(2,1,-2)&C(-5,2,-6) are the position vectors of the vertices of a triangle ABC.The length of the bisector of its internal angle at A is :

A(1,3) and C(-2,/5, -2/5) are the vertices of a triangle ABC and the equation of the internal angle bisector of angleABC " is " x+y=2. The equation of side BC is

A (1,3) and C (-2/5,-2/5) are the vertices of a triangle ABC and the equation of the internal angular bisector of angleABC is x+y -2=0 Coordinates of vertex B