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Let the line (x-2)/3=(y-1)/(-5)=(z+2)/2 ...

Let the line `(x-2)/3=(y-1)/(-5)=(z+2)/2` lie in the plane `x+3y-alphaz+beta=0. Then (alpha,beta) equals (A) `(6,-17)` (B) `(-6,7)` (C) `(5,15)` (D) `(-5,5)`

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