`NH_(4)HS(s)hArrNH_(3)(g)+H_(2)S(g)`
`The3 equilibrium pressure at `25^(@)C` is 0.660 atm . What is `K_(p)` for the reaction ?

NH_(4)HS(s)hArrNH_(3)(g)+H_(2)S(g) The equilibrium pressure at 25^(@)C is 0.660 atm . What is K_(p) for the reaction?

NH_(4)HS(s)hArrNH_(3)(g)+H_(2)S(g) The equilibrium pressure at 25 degree Celsius is 0.660 atm . What is Kp for the reaction ?

NH_(4)HS_(s)hArrNH_(3(g))+H_(2)S_(g) The equilibrium pressure at 25_(@) C is 0.660 atm What is K_(p) for reactoin ? NH_(4)NH_(s)hArrNH_(3(g))+H_(2)S_(g)

NH_(4)COONH_(2)(s)hArr2NH_(3)(g)+CO_(2)(g) If equilibrium pressure is 3 atm for the above reaction, then K_(p) for the reaction is

NH_(4)COONH_(2)(s)hArr2NH_(3)(g)+CO_(2)(g) If equilibrium pressure is 3 atm for the above reaction, then K_(p) for the reaction is

NH_(4)COONH_(2)(s)hArr2NH_(3)(g)+CO_(2)(g) If equilibrium pressure is 3 atm for the above reaction, then K_(p) for the reaction is

For the reaction NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g) in a closed flask, the equilibrium pressure is P atm. The standard free energy of the reaction would be: