The longest ` lambda` for the Lyamn series is …………… (Given ` R_H = 109678 cm^(-1))` :

The longest lambda for the Lyman series is…. (Given R_H=109678 cm^(-1) ):

The shortest lambda for the Lyman series is…. (Given R_H=109678 cm^(-1) ):

The shortest lambda for the Lyman series of hydrogen atom is _______(given R_H=109678 cm^-1 )

Calculate the wavelengths of the first line and the series limit for the Lyman series for hydrogen (R_(H)=109678 cm^(-1)) .

Calculate the shortest and longest wavelength I hydrogen spectrum of Lyman series. or Calculate the wavelength of the first line and the series limit for the Lyman series of hydrogen. (R_(H)=109678cm^(-1)) .

The shotest wave length in H spectrum of Lymen series when R_(H) = 109678cm^(-1) is.

The wave number of the series limiting line for the Lyman series for hydrogen atom is (R =109678cm^(-1) )

The wave number of the series limiting line for the Lyman series for hydrogen atom is (R = 109678 cm^-1 )

What hydrogen-like ion has the wavelength difference the first lines of Balmer and Lyman series equal to 59.3 nm ? R_(H) = 109.678 cm^(-1)

Calculate the wavelength of the first spectral line of the Balmer series in hydrogen spectra. (Give R_H = 1.09737 cm^(-1) )