The complex number `z_1 z_2 z_3` are the vertices of a triangle .Then the complex number z which make the triangle into parallelogram is

Let the complex numbers z_1,z_2 and z_3 be the vertices of an equilateral triangle let z_0 be the circumcentre of the triangle. Then prove that z_1^2+z_2^2+z_3^2= 3z_0^2

Let the complex numbers z_1,z_2 and z_3 be the vertices of an equilateral triangle let z_0 be the circumcentre of the triangle. Then prove that z_1^2+z_2^2+z_3^2= 3z_0^2

Let the complex numbers z_1,z_2 and z_3 be the vertices of an equilateral triangle let z_0 be the circumcentre of the triangle then prove that z_1^2+z_2^2+z_3^2=3z_0^2

The complex numbers z_(1), z_(2), z_(3) are three vertices of a parallelogram taken in order then the fourth vertex is

Let the complex number z_(1) , z_(2) , z_(3) be the vertices of an equilateral triangle . Let z_(theta) be the circumcentre of the triangle . Then z_(1)^(2) + z_(2)^(2) + z_(3)^(2) =

Let the complex numbers z_1,z_2,z_3 be the vertices of an equilateral triangle. Let z_0 be the circumcentre of the triangle. Then prove that z_1^2+z_2^2+z_3^2= 3z_0^2 .

If the complex numbers iz,z and z+iz represent the three vertices of a triangle,then the area of the triangle is