`Psi_((r)) = ke^(-r//k_(1)) dot" r^(2) (r^(2) - k_(2)r + k_(3))` . If the orbital has no nodal plane , then , orbital can be :

Psi_(r) =k_(1) e^(-r//k_(2))(r^(2)-5k_(3) r+6K_(3)^(2)) For the above orbital match the column-I with column-II (assuming ,k_(3)=1 )

(A) There are two nodal regions in 3s-orbital (R) : There is no nodal plane in 3s orbital The correct answer is

(A) There are two noda regions in 3s-orbital (R) : There is no nodal plane in 3x orbital The correct answer is

(A) There are two noda regions in 3s-orbital (R) : There is no nodal plane in 3s orbital The correct answer is

A 4pir^(2)Psi^(2)(r) vs" " r is ploted for H-orbital curve contains '3'maxima . If orbital contains 2 angular node then orbital is

For an orbital , having no planar angular nodes following the equation : Psi_((r)) = Ke^(-r//K') dot" r^(2)(K'' -r) Identify the orbital :

In a triangle ABC, if (r_(1)+r_(2))(r_(2)+r_(3))(r_(3)+r_(1))4RK then k=