In a solid ,oxide `(O^(2-))` ions are arranged in ccp, cations `(A^(3+))` occupy one -sixth of tetrahedral void and cations `(B^(3+))` occupy one -third of the octahedral voids . What is the formula of the compound?

In a solid ,oxide (O^(2-)) ions are arranged in ccp, cations (A^(3+)) occupy one -fourth of tetrahedral void and cations (B^(3+)) occupy half of the octahedral voids . What is the formula of the compound?

In a solid, oxide ions are arranged in ccp. Cations 'A' occupy one - sixth of the tetrahedral voids and cations 'B' occupy one - third of the octahedral voids. Which of the following is the correct formula of the oxide?

In a compound,oxide ions are arranged in cubic close packing arrangement. Cations A occupy one-sixth of the tetrahdral voids and cations B occupy one-third of the octahedral voids. The formula of the compound is

In a compound,oxide ions are arranged in cubic close packing arrangement. Cations A occupy one-sixth of the tetrahdral voids and cations B occupy one-third of the octahedral voids. The formula of the compound is

In a compound oxide ions are arranged in cubic close packing arrangement. Cations A occupy one-sixth of the tetrahedral voids and cations B occupy one-third of the octahdral voids. The formual of the compound is A_(x), B_(y), O_(z) then find the value of x + y + z

In a solid, oxide ions are arrnged in ccp, cations A occupy A occupy (1/8)^th of the tetrahedral voids and cation B occupy (1/4)^(th) of the octahedral voids. The formula of the compound is:

In a solid, oxide ions are arrnged in ccp, cations A occupy A occupy (1/8)^th of the tetrahedral voids and cation B occupy (1/4)^(th) of the octahedral voids. The formula of the compound is: