`int t/(t+b^2) dt`

Evaluate indefinite integration. (i) x=intdt " " (ii) int t dt " " (iii) x=int (2t) dt" " (iv) x=int (t^(2)) dt " " (v) x=int (-(2)/(t^3))dt

int sqrt(t)dt

int (-1)/(t-1) dt - int 1/t dt

Find the derivative with respect to x of the following functions : (a) F(x) = int_(0)^(2x) (sin t)/(t) dt , (b) f(x) = int_(x)^(0) sqrt(1 + t^(4)) dt

1/2 int (dt)/(1 + t)

Integrate the following function (a) int_(o)^(2) 2t dt (b) int _(1) ^(2)(2t -4) dt

int(2t^(2))/(t^(2)+t-2)backslash dt

int(t+2)/((t^(2)+4t+2))dt

A=int_(1)^(sin theta)(t)/(1+t^(2))dt;B=int_(1)^(cos ec theta)(1)/(t(1+t^(2)))dt then find the value of the given determinant