A circle passes through the origin and has its center on `y=x` If it cuts `x^2+y^2-4x-6y+10=-` orthogonally, then find the equation of the circle.

A circle passes through the origin and has its center on y=x If it cuts x^2+y^2-4x-6y+10=0 orthogonally, then find the equation of the circle.

A circle passes through origin and has its centre on y = x . If it cuts x^(2) + y^(2) - 4x - 6y + 10 = 0 orthogonally then the equation of the circle is

A circle passes through origin and has its centre on y = x. If it cuts x^2+y^2-4x-6y+10=0 orthogonally then the equation of the circle is

If a circle passes through the point (a, b) and cuts the circle x^2 +y^2=k^2 orthogonally, then the equation of the locus of its center is

If a circle passes through the point (a, b) and cuts the circle x^2 +y^2=k^2 orthogonally, then the equation of the locus of its center is

If a circle passes through the point (a,b) and cuts the circle x^(2)+y^(2)=k^(2) orthogonally, then the equation of the locus of its center is

If a circle passes through the point (3,4) and cuts the circle x ^(2) + y ^(2) =a ^(2) orthogonally, the equation of the locus of its centre is