" If "sqrt(1-c^(2))=nc-1" and "z=e^(i theta)," then "(c)/(2n)(1+nz)(1+(n)/(z))" is çual to: "

If sqrt(1-c^(2))=nc-1andz=e^(itheta)," then "(c)/(2n)(1+nz)(1+(n)/(z)) is equal to :

If sqrt(1-c^(2))=nc-1andz=e^(itheta)," then "(c)/(2n)(1+nz)(1+(n)/(z)) is equal to :

|z|=1&z^(2n)+1!=0 then (z^(n))/(z^(2n)+1)-(z^(n))/(z^(2n)+1) is equal to

If n is an integer and z=cos theta+i sin theta , then (z^(2 n)-1)/(z^(2 n)+1)=

If z + (1)/(z) = 2 cos theta, z in "C then z"^(2n) - 2z^(n) cos (n theta) is equal to

(1+i)^(2 n)+(1-i)^(2 n), n in z is

If n is an integer and z=cis theta,(theta ne (2n+1)pi/2), then show that (z^(2n)-1)/(z^(2n)+1)=i tan n theta) .