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An electromagnetic wave of frequency v=3...

An electromagnetic wave of frequency `v=3.0 MHz` passes from vacuum into a dielectric medium with permittivity `epsilon=4.0`. Then

A

wavelength is halved and frequency remains unchanged

B

wavelength is doubled and frequency becomes half

C

wavelength is doubled and the frequency remains unchanged

D

wavelength and frequency both remain unchanged

Text Solution

Verified by Experts

The correct Answer is:
A

Frequency remains constant during refraction
`v_("med")=(1)/(sqrt(mu_(0)in_(0)xx4))=(c )/(2)(lambda_("med"))/(lambda_("air"))=(v_("med"))/(v_("air"))=(c//2)/(c)=(1)/(2)`
`therefore` wavelength is halved and frequency remains unchanged.
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