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The ratio of amplitude of magnetic field...

The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacumm is equal to

A

the speed of light in vacuum

B

reciprocal of speed of light in vacuum

C

the ratio of magnetic permeability to the electric susceptibility of vacuum

D

unity

Text Solution

Verified by Experts

The correct Answer is:
B

The average energy stored in the electric field and magnetic field respectively are
`U_(E )=(1)/(2)epsilon_(0)E^(2) and U_(B)=(1)/(2)(B^(2))/(mu_(0))`,
According to conservation of energy `U_(E)=U_(B)`
`epsilon_(0)mu_(0)=(B^(2))/(E^(2))rArr (B)/(E)=sqrt(epsilon_(0)mu_(0))=(1)/(C )`
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