Light takes `t_(1)` second to travel a distance x cm in vacuum and the same light takes `t_(2)` second to travel 10x cm in medium. The critical angle for the corresponding medium is

Options

A. `sin^(-1)((10t_(2))/(t_(1)x))`
B. `sin^(-1)((t_(2)x)/(10t_(1)))`
C. `sin^(-1)((10t_(1))/(t_(2)x))`
D. `sin^(-1)((t_(1)x)/(10t_(2)))`

Answer

C

Explanation

`c=(x)/(t_(1)), v=(10)/(t_(2))`
`sini_(c)=(1)/(mu)=(v)/(c)=(10)/(t_(2))xx(t_(1))/(x), i_(c)=sin^(-1)((10t_(1))/(t_(2)x))`