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An AM wave is expressed as e=10(1+0.6cos...

An `AM` wave is expressed as `e=10(1+0.6cos2000pit)cos2xx10^(8)pit "volts"`, the minimum and maximum values of modulated carrier wave are

A

10V and 20 V

B

4V and 8V

C

16 V and 4V

D

8 V and 20 V

Text Solution

Verified by Experts

The correct Answer is:
C
`E_("max") = (1 + m_a) E_c= ( 1+ 0.6) xx 10 = 16 V `
`E_("min") =( 1- m_a)E_c = (1-0.6) xx 10 = 4 V `.
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DISHA PUBLICATION-COMMUNICATION SYSTEM -EXERCISE-2 : Concept Applicator
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