A carrier frequency of 10kV at 1 MHz is amplitude modulated by a 1 kHz signal of 6 kV peak voltage. When the modulation pattern is observed on a calibrated CRO, the voltage indicated by the CRO will be

Options

A. 16
B. 32
C. 864
D. 84

Explanation

To solve the problem, we need to determine the voltage indicated by the calibrated CRO when observing the amplitude-modulated signal. Here’s a step-by-step breakdown of the solution:

### Step 1: Understand the Components
- **Carrier Voltage (Vc)**: This is the voltage of the carrier wave, which is given as 10 kV.
- **Modulating Signal Voltage (Vm)**: This is the peak voltage of the modulating signal, given as 6 kV.
- **Modulation Frequency**: The frequency of the modulating signal is 1 kHz, but this is not directly needed to calculate the voltage observed on the CRO.

### Step 2: Calculate the Peak-to-Peak Voltage
The voltage observed on the CRO for an amplitude-modulated signal can be calculated using the formula for peak-to-peak voltage:

\[ V_{pp} = V_c + V_m \times 2 \]

Where:
- \( V_{pp} \) is the peak-to-peak voltage observed on the CRO.
- \( V_c \) is the carrier voltage.
- \( V_m \) is the peak voltage of the modulating signal.

### Step 3: Substitute the Values
Now, substituting the values into the formula:

\[ V_{pp} = 10 \text{ kV} + (6 \text{ kV} \times 2) \]

### Step 4: Perform the Calculation
Calculating the modulating signal contribution:

\[ V_{pp} = 10 \text{ kV} + 12 \text{ kV} = 22 \text{ kV} \]

### Step 5: Final Calculation
Now, we need to sum the carrier voltage and the modulating signal contribution:

\[ V_{pp} = 10 \text{ kV} + 12 \text{ kV} = 22 \text{ kV} \]

### Step 6: Conclusion
The voltage indicated by the CRO will be:

\[ \text{Voltage indicated by CRO} = 22 \text{ kV} \]

### Final Answer:
The voltage indicated by the CRO will be **22 kV**.

---