`KO_(2)+CO_(2)+H_(2)O overset("more "CO_(2))rarr [X]+[Y]`
Products [X] and [Y] are respectively:

Answer

To solve the question, we need to analyze the reaction between potassium superoxide (KO₂), carbon dioxide (CO₂), and water (H₂O) in the presence of excess CO₂.

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in the equation are KO₂, CO₂, and H₂O.

2. **Understand the Reaction**: When KO₂ reacts with CO₂ and H₂O, it produces potassium hydrogen carbonate (KHCO₃) and oxygen (O₂). The presence of excess CO₂ indicates that it will further react with water.

3. **Write the Balanced Chemical Equation**: The balanced equation for the reaction can be written as:
\[ 4 KO₂ + 2 CO₂ + 2 H₂O \rightarrow 4 KHCO₃ + O₂ \]
This equation shows that four moles of potassium superoxide react with two moles of carbon dioxide and two moles of water to produce four moles of potassium hydrogen carbonate and one mole of oxygen gas.

4. **Identify the Products**: From the balanced equation, we can see that the products are:
- [X] = O₂ (oxygen gas)
- [Y] = KHCO₃ (potassium hydrogen carbonate)

5. **Conclusion**: Therefore, the products [X] and [Y] are respectively:
- [X] = O₂
- [Y] = KHCO₃

### Final Answer:
- Products [X] and [Y] are respectively:
- [X] = O₂
- [Y] = KHCO₃