Home
Class 12
CHEMISTRY
Reaction of diborane with ammonia gives ...

Reaction of diborane with ammonia gives initially

A

`B_(2)H_(6).NH_(3)`

B

Borazole

C

`B_(2)H_(6).3NH_(3)`

D

`[BH_(2)(NH_(3))_(2)]^(+)[BH_(4)]^(-)`

Text Solution

Verified by Experts

The correct Answer is:
D
`B_(2)H_(6) +NH_(3) overset("excess"NH_(3))underset("low temperature") rarr B_(2)H_(6).2NH_(3)`
Diborane with ammonia gives `B_(2)H_(6).2NH_(3)` that is formulated as `[BH_(2)(NH_(3))]^(+)[BH_(4)]^(-)` which when heated to 473 K decomposes to give borazole.
Promotional Banner

Topper's Solved these Questions

  • The p-Block Elements (Group 13 and Group 14)

    DISHA PUBLICATION|Exercise Exercise-1: Concept Builder (Topicwise) TOPIC 2: Carbon Family|28 Videos

  • The p-Block Elements (Group 13 and Group 14)

    DISHA PUBLICATION|Exercise Exercise-2: Concept Applicator|30 Videos

  • The p-Block Elements (Group 13 and Group 14)

    DISHA PUBLICATION|Exercise Exercise-2: Concept Applicator|30 Videos

  • THE D- AND F- BLOCK ELEMENTS

    DISHA PUBLICATION|Exercise EXERCISE - 2 CONCEPT APPLICATOR|30 Videos

  • THE P-BLOCK ELEMENTS (GROUP 15, 16, 17 & 18)

    DISHA PUBLICATION|Exercise Exercise|110 Videos

Similar Questions

Explore conceptually related problems

In diborane

In diborane

Reaction of ammonia with diborane gives initially B_(2) H_(6) 2NH_(3) which can also be written as

Reaction of formadehyde and ammonia gives

The product obtained in the reaction of diborane with excess of ammonia at low temperature is:

Phenol on treatement with ammonia gives-

Reaction With Ammonia