When Sn is treated with conc. `HNO_(3)`

Options

A. it is converted into stannous nitrate.
B. it is converted into stannic nitrate.
C. it is converted into metastannic acid.
D. it becomes passive.

Explanation

To solve the question "When Sn is treated with conc. HNO3", we will analyze the reaction step by step.

### Step 1: Identify the Reactants
The reactants in this scenario are tin (Sn) and concentrated nitric acid (HNO3).

**Hint:** Always start by identifying the substances involved in the reaction.

### Step 2: Understand the Properties of Tin
Tin is a soft, white, silvery metal that is resistant to corrosion due to a protective oxide layer. It belongs to Group 14 of the periodic table.

**Hint:** Knowing the properties of the reactants can help predict the products of the reaction.

### Step 3: Reaction with Concentrated Nitric Acid
When tin reacts with concentrated nitric acid, it undergoes oxidation. The concentrated nitric acid is a strong oxidizing agent.

**Hint:** Consider the behavior of strong acids and oxidizing agents when they react with metals.

### Step 4: Write the Balanced Chemical Equation
The reaction can be represented as follows:

\[ \text{Sn} + 4 \text{HNO}_3 \rightarrow \text{H}_2\text{SnO}_3 + 4 \text{NO}_2 + 2 \text{H}_2\text{O} \]

In this reaction, tin (Sn) is oxidized to form stannic acid (H2SnO3), nitrogen dioxide (NO2), and water (H2O).

**Hint:** Balancing the equation is crucial to ensure that the number of atoms for each element is conserved.

### Step 5: Identify the Product
From the balanced equation, we can see that the primary product formed when tin reacts with concentrated nitric acid is stannic acid (H2SnO3).

**Hint:** Focus on the products formed in the reaction to answer the question accurately.

### Conclusion
When tin (Sn) is treated with concentrated nitric acid (HNO3), it is converted into stannic acid (H2SnO3), along with nitrogen dioxide (NO2) and water (H2O).

**Final Answer:** The correct option is that Sn is converted into stannic nitrate (H2SnO3).