To a piece of charcoal, sulphuric acid is added. Then:

Options

A. There is no reaction.
B. Water gas is formed.
C. `SO_(2) and CO_(2)` are evolved
D. `CO and SO_(2)` are evolved

Explanation

To solve the question regarding the reaction between charcoal (pure carbon) and sulfuric acid, we will follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are charcoal (carbon, C) and sulfuric acid (H₂SO₄).

### Step 2: Understand the Reaction Conditions
The reaction is typically conducted with hot concentrated sulfuric acid. This is important as it influences the products formed.

### Step 3: Write the Reaction Equation
When carbon reacts with sulfuric acid, it can be represented by the following unbalanced equation:
\[ \text{C} + \text{H}_2\text{SO}_4 \rightarrow \text{SO}_2 + \text{CO}_2 + \text{H}_2\text{O} \]

### Step 4: Balance the Reaction
To balance the reaction, we need to ensure that the number of atoms of each element is the same on both sides of the equation. The balanced equation is:
\[ 2\text{C} + 2\text{H}_2\text{SO}_4 \rightarrow 2\text{SO}_2 + 2\text{CO}_2 + 2\text{H}_2\text{O} \]

### Step 5: Identify the Products
From the balanced equation, we can see that the products formed are:
- Sulfur dioxide (SO₂)
- Carbon dioxide (CO₂)
- Water (H₂O)

### Step 6: Determine the Gases Evolved
In this reaction, the gases evolved are sulfur dioxide (SO₂) and carbon dioxide (CO₂).

### Step 7: Conclusion
Thus, when a piece of charcoal is added to sulfuric acid, the gases evolved are SO₂ and CO₂.

### Final Answer
The correct option is: **SO₂ and CO₂ are evolved.**

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