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A ball projected with a velocity of 2...

A ball projected with a velocity of 28 m/sec has a horizontal range 40 m. Find the two angles of projection.

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A ball projected with a velocity of 28m/sec has a horizontal range 40m. Find the two angles of projection.

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A body is projected with a velocity of 30m/s to have to horizontal range of 45m. Find the angle of projection .

A particle is thrown with a velocity 10 m//s and its horizontal range is 5 m . Find angle/angles of the projection.

Prove that for a given velocity of projection, the horizontal range is same for two angles of projection alpha and (90^(@) - alpha) .

Assertion: Horizontal range is same for angle of projection theta and (90^(@)- theta) . Reason : Horizontal range is independent of angle of projection.

Assertion: Horizontal range is same for angle of projection theta and (90^(@)- theta) . Reason : Horizontal range is independent of angle of projection.