Home
Class 12
MATHS
The area enclosed by the curve y=sqrt(4-...

The area enclosed by the curve `y=sqrt(4-x^2),ygeqsqrt(2)sin((xpi)/(2sqrt(2)))` , and the `x-a xi s` is divided by the `y-a xi s` in the ratio. `(pi^2-8)/(pi^2+8)` (b) `(pi^2-4)/(pi^2+4)` `(pi-4)/(pi-4)` (d) `(2pi^2)/(2pi+pi^2-8)`

Promotional Banner

Similar Questions

Explore conceptually related problems

The area enclosed by the curve y=sqrt(4-x^2),ygeqsqrt(2)sin((xpi)/(2sqrt(2))) , and the x-axis is divided by the y-axis in the ratio. (a) (pi^2-8)/(pi^2+8) (b) (pi^2-4)/(pi^2+4) (c) (pi-4)/(pi-4) (d) (2pi^2)/(2pi+pi^2-8)

The area enclosed by the curve y=sqrt(4-x^2),ygeqsqrt(2)sin((xpi)/(2sqrt(2))) , and the x-axis is divided by the y-axis in the ratio. (a) (pi^2-8)/(pi^2+8) (b) (pi^2-4)/(pi^2+4) (c) (pi-4)/(pi-4) (d) (2pi^2)/(2pi+pi^2-8)

The equation of normal to the curve y=sqrt(2) sin (2x+(pi)/(4))" at "x=(pi)/(4) is

The equation of tangent to the curve y=sqrt(2) sin (2x+(pi)/(4))" at "x=(pi)/(4) is

Area enclosed by the curve (y-sin^(- 1)x)^2=x-x^2 , is (A) pi/2 sq.units (B) pi/4 sq.units (C) pi/8 sq.units (D) none of these

Area enclosed by the curve (y-sin^(-1)x)^(2)=x-x^(2), is (A) (pi)/(2) sq.units (B) (pi)/(4) sq.units (C) (pi)/(8) sq.units (D) none of these

The area bounded by the curves x^(2)+y^(2)=1,x^(2)+y^(2)=4 and the pair of lines sqrt(3)x^(2)+sqrt(3)y^(2)=4xy ,in the first quadrant is (1)(pi)/(2)(2)(pi)/(6)(3)(pi)/(4)(4)(pi)/(3)

The area in the first quadrant between x^2+y^2=pi^2 and y=sinx is (a) ((pi^(3)-8))/(4) (b) (pi^(3))/(4) (c) ((pi^(3)-16))/(4) (d) ((pi^(3)-8))/(2)

If f(x)=sin x-x, then int_(-2 pi)^(2 pi)|f^(-1)(x)|dx= (A) pi^(2)(B)2 pi^(2)(C)3 pi^(2)(D)4 pi^(2)

The area bounded by y= sin^(2)x, x = (pi)/(2) and x=pi is a) (pi)/(2) b) (pi)/(4) c) (pi)/(8) d) (pi)/(16)