The radius of a nucleus is given by `r_(0) A^(1//3)` where `r_(0) = 1.3xx 10^(-15)` m and A is the mass number of the nucleus, the Lead nucleus has A = 206. the electrostatic force between two protons in this nucleus is approximately

If A is mass number of a nucleus of Radius R, then

Radius of a nucleus is given by the relation R = R_(0)A^(1//3) where R_(0) = 1.3 xx 10^(-15) m and A is mass number. For a nucleon inside a nucleus, de-Broglie wavelength is given by diameter of the nucleus. Average kinetic energy of a nucleon in the Te^(128) nucleus based on above information will be :

Radius of a nucleus is given by the relation R = R_(0)A^(1//3) where R_(0) = 1.3 xx 10^(-15) m and A is mass number. For a nucleon inside a nucleus, de-Broglie wavelength is given by diameter of the nucleus. Average kinetic energy of a nucleon in the Te^(128) nucleus based on above information will be :

The radius of ""_(29) Cu^(64) nucleus in Fermi is (given R_(0) = 1.2 xx 10^(-15) m )

The radius of nucleus is R=R_(0)A^(1//3) where A is the mass number of the atom. What are the dimensions of R_(0) ?

The radius of a nucleus of mass number 'A' is given by R = 1.3 xx 10^-16 xx A^(1//3) . Find the order of magnitude of radius for a nucleus with A = 216.

The radius of nucleus is r=r_(0)A^(1//3) , where A is mass number. The dimensions of r_(0) is