The shortest distance between the lines `vec(r)=vec(a)+tvec(b)` and `vec(r)=vec(a)'+svec(b)` is

The shortest distance between the lines vec(r)=vec(a)_(1)+tvec(b)_(1) and vec(r)=vec(a)_(2)+svec(b)_(2) is -

The condition for intersecting the lines vec(r)=vec(a)_(1)+tvec(b)_(1) and vec(r)=vec(a)_(2)+svec(b)_(2) is

Write the formula for the shortest distance between the lines vec r= vec a_1+lambda vec b_1 a n d\ vec r= vec a_2+mu vec b_2dot\

The condition for collinearity for the two parallel lines vec(r)=vec(a)+tvec(b)" and " vec(r)=vec(a)_(1)+svec(b) is

Derive the formula for the distance between two parallel lines vec(r)=vec(a_(1))+lambdavec(b) and vec(r)=vec(a_(2))+muvec(b) in vector form.

Obtain the distance betweenn two parallel lines vec(r)=vec(a)_(1)+lambdavec(b), vec(r)=vec(a)_(2)+muvec(b) .

Let A( vec a)a n dB( vec b) be points on two skew lines vec r= vec a+lambda vec pa n d vec r= vec b+u vec q and the shortest distance between the skew lines is 1, w h e r e vec pa n d vec q are unit vectors forming adjacent sides of a parallelogram enclosing an area of 1/2 units. If angle between A B and the line of shortest distance is 60^0, then A B= a. 1/2 b. 2 c. 1 d. lambda R={0}

Let A( vec a)a n dB( vec b) be points on two skew lines vec r= vec a+lambda vec pa n d vec r= vec b+u vec q and the shortest distance between the skew lines is 1, w h e r e vec pa n d vec q are unit vectors forming adjacent sides of a parallelogram enclosing an area of 1/2 units. If angle between A B and the line of shortest distance is 60^0, then A B= a. 1/2 b. 2 c. 1 d. lambda R={10}