A uniform chain of mass `M` and length `L` is lying on a frictionless table in such a way that its `1//3` parts is hanging vertically down. The work done in pulling the chain up the table is

A uniform chain has mass Mand length L. It is lying on a smooth horizontal table with half of its length hanging vertically downward. The work done in pulling the chain up the table is:

A chain of uniform mass m and length L is held on a frictionless table in such a way that its (1)/(n) th part is hanging below the edge of table. The work done to pull the hanging part of chain is :-

A chain of uniform mass m and length L is held on a frictionless table in such a way that its (1)/(n) th part is hanging below the edge of table. The work done to pull the hanging part of chain is :-

A chain of uniform mass m and length L is held on a frictionless table in such a way that its (1)/(n) th part is hanging below the edge of table. The work done to pull the hanging part of chain is :-

A uniform chain has a mass m and length l . It is held on a frictionless table with one - sixth of its length hanging over the edge. The work done in just pulling the hanging part back on the table is :

A uniform chain of mass m and length l is kept on a horizontal table with half of its length hanging from the edge of the table.Work done in pulling the chain on to the table so that only 1/5 th of its length now hangs from the edge is K((mgl)/(200)) .Find the value of K.

A uniform chain of mass.m. and length .L. is kept on a horizontal table with half of its length hanging from the edge of the table. Work done in pulling the chain on to the table so that only 1/5 th of its length now hangs from the edge is