In a photo-emissive cell, with exciting wavelength `lambda_1`, the maximum kinetic energy of electron is K. If the exciting wavelength is changed to `lambda_2`, the maximum kinetic energy of electron is 2K then

In a photo-emissive cell, with exciting wavelength lambda , the maximum kinetic energy of electron is K. If the exciting wavelength is changed to ( 3 lambda)/( 4) the kinetic energy of the fastest emitted electron will be :

The maximum kinetic energy of the photo electron is

In a photoemissive cell, with exciting wavelength lambda , the faster electron has speed v. If the exciting wavelength is changed to 3lambda//4 , the speed of the fastest electron will be

In a photoemissive cell, with exciting wavelength lambda , the faster electron has speed v. If the exciting wavelength is changed to 3lambda//4 , the speed of the fastest electron will be

If the kinetic energy of a electron , it's debroglie wavelength changes by the factor

If light of wavelength lambda_(1) is allowed to fall on a metal , then kinetic energy of photoelectrons emitted is E_(1) . If wavelength of light changes to lambda_(2) then kinetic energy of electrons changes to E_(2) . Then work function of the metal is

If light of wavelength lambda_(1) is allowed to fall on a metal , then kinetic energy of photoelectrons emitted is E_(1) . If wavelength of light changes to lambda_(2) then kinetic energy of electrons changes to E_(2) . Then work function of the metal is

If a metal is exposed with light of wavelength lambda, the maximum kinetic energy produced is found to be 2 eV. When the same metal is exposed to a wavelength (lambda)/(5) the maximum kinetic energy was found to be 14 eV. Find the value of work function (in eV).

Initially a photon of wavelength lambda_(1) falls on the photocathode and emits of maximum energy E_(1) .If the wavelength of the incident photon is changed to lambda_(2) the maximum energy of the electron emitted becomes E_(2) .Then value of he (h=Planck's constant,c= velocity of light) is