The equations of the three circles are x...

The equations of the three circles are `x^2+y^2-6x-6y+4=0 , x^2+y^2-2x-4y+3=0` and `x^2+y^2+2kx+2y+1=0`. If the radical centre of above three circles exist then which of the following can not be the value of `k`

Similar Questions

Explore conceptually related problems

x^(2) + y^(2) -6x -6y + 4 = 0, x^(2) + y^(2) -2x -4y + 3 = 0 , x^(2) + y^(2) + 2kx + 2y + 1 = 0 . If the radical centre of the above three circles exists, then which of the following cannot be the value of k?

The radical center of the circles x^(2)+y^(2)-4x-6y+5=0 , x^(2)+y^(2)-2x-4y-1=0 , x^(2)+y^(2)-6x-2y=0 .

Prove that the centres of the three circles : x^2 + y^2 -4x-6y-14=0, x^2 + y^2+ 2x+4y-5=0 and x^2 + y^2-10x -16y + 7 = 0 are collinear.

The equation of the circle which cuts the three circles x^2+y^2-4x-6y+4=0, x^2+y^2-2x-8y+4=0, x^2+y^2-6x-6y+4=0 orthogonally is

Find the radical centre of the following circles x^2+y^2-4x-6y+5=0 x^2+y^2-2x-4y-1=0 x^2+y^2-6x-2y=0

The equations of the three circles are `x^2+y^2-6x-6y+4=0 , x^2+y^2-2x-4y+3=0` and `x^2+y^2+2kx+2y+1=0`. If the radical centre of above three circles exist then which of the following can not be the value of `k`

Similar Questions

Recommended Questions