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In a school , the average age of student...

In a school , the average age of students is 6 years , and the average age of 12 teachers is 40 years . If the average age of the combined group of all the teachers and students is 7 years , then the number of student is :

A

396

B

400

C

408

D

416

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the information given about the average ages of students and teachers, and the combined average age of both groups. ### Step 1: Define Variables Let: - \( n \) = number of students - The average age of students = 6 years - The average age of teachers = 40 years - Number of teachers = 12 - Combined average age of students and teachers = 7 years ### Step 2: Calculate Total Ages Calculate the total age of the teachers: \[ \text{Total age of teachers} = \text{Average age of teachers} \times \text{Number of teachers} = 40 \times 12 = 480 \text{ years} \] Calculate the total age of the students: \[ \text{Total age of students} = \text{Average age of students} \times \text{Number of students} = 6n \] ### Step 3: Set Up the Equation for Combined Average The combined average age of students and teachers is given as 7 years. The total number of individuals (students + teachers) is \( n + 12 \). Therefore, we can set up the equation: \[ \text{Combined average} = \frac{\text{Total age of students} + \text{Total age of teachers}}{\text{Total number of individuals}} \] Substituting the known values: \[ 7 = \frac{6n + 480}{n + 12} \] ### Step 4: Clear the Fraction Multiply both sides by \( n + 12 \) to eliminate the fraction: \[ 7(n + 12) = 6n + 480 \] ### Step 5: Expand and Rearrange the Equation Expanding the left side: \[ 7n + 84 = 6n + 480 \] Now, rearranging the equation to isolate \( n \): \[ 7n - 6n = 480 - 84 \] \[ n = 396 \] ### Conclusion The number of students \( n \) is 396. ---
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