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A reduction of 33(1)/3% in the price of ...

A reduction of `33(1)/3`% in the price of an item would enable a purchaser to get 4 more a rupee. No' of item price before reduction was :

A

2 per rupee

B

4 per rupee

C

12 per rupee

D

8 per rupee

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will first understand the given information and then derive the required solution. ### Step 1: Understand the Reduction Percentage The problem states that there is a reduction of \(33 \frac{1}{3}\%\) in the price of an item. This can be converted to a fraction: \[ 33 \frac{1}{3}\% = \frac{33.33}{100} = \frac{1}{3} \] ### Step 2: Determine the Price After Reduction If the original price of the item is \(P\), after a reduction of \(33 \frac{1}{3}\%\), the new price \(P'\) can be calculated as: \[ P' = P - \frac{1}{3}P = \frac{2}{3}P \] ### Step 3: Understand the Effect of Price Reduction According to the problem, after the price reduction, a purchaser can buy 4 more items for the same amount of money (1 rupee). This means that if the original price allowed the buyer to buy \(x\) items for 1 rupee, after the reduction, they can buy \(x + 4\) items for the same 1 rupee. ### Step 4: Set Up the Equation The number of items that can be bought before the reduction is given by: \[ x = \frac{1}{P} \] After the reduction, the number of items that can be bought is: \[ x + 4 = \frac{1}{P'} \] Substituting \(P' = \frac{2}{3}P\) into the equation gives: \[ x + 4 = \frac{1}{\frac{2}{3}P} = \frac{3}{2P} \] ### Step 5: Substitute the Value of \(x\) Now substituting \(x = \frac{1}{P}\) into the equation: \[ \frac{1}{P} + 4 = \frac{3}{2P} \] ### Step 6: Clear the Denominator To eliminate the denominators, multiply through by \(2P\): \[ 2 + 8P = 3 \] ### Step 7: Solve for \(P\) Rearranging the equation gives: \[ 8P = 3 - 2 \] \[ 8P = 1 \] \[ P = \frac{1}{8} \] ### Step 8: Calculate the Number of Items Before Reduction The number of items that could be bought before the reduction is: \[ x = \frac{1}{P} = \frac{1}{\frac{1}{8}} = 8 \] ### Final Answer The number of items that could be bought before the reduction was **8 items per rupee**. ---
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