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Ganga and Saraswati, working separately ...

Ganga and Saraswati, working separately can now a field in 8 and 12 hours respectively. If they work in stretches of one hour alternately, Ganga beginning at 9 a.m., when will the moving be completed ?

A

6 p.m .

B

6.30 a.m.

C

5 p.m.

D

5.30 p.m.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine when Ganga and Saraswati will complete the work if they alternate working on it for one hour each, starting with Ganga at 9 a.m. ### Step-by-Step Solution: 1. **Determine the Work Rates:** - Ganga can complete the field in 8 hours. Therefore, her work rate is: \[ \text{Work Rate of Ganga} = \frac{1 \text{ field}}{8 \text{ hours}} = \frac{1}{8} \text{ fields per hour} \] - Saraswati can complete the field in 12 hours. Therefore, her work rate is: \[ \text{Work Rate of Saraswati} = \frac{1 \text{ field}}{12 \text{ hours}} = \frac{1}{12} \text{ fields per hour} \] 2. **Calculate the Amount of Work Done in 2 Hours:** - In the first hour (9 a.m. to 10 a.m.), Ganga works and completes: \[ \text{Work done by Ganga} = \frac{1}{8} \text{ fields} \] - In the second hour (10 a.m. to 11 a.m.), Saraswati works and completes: \[ \text{Work done by Saraswati} = \frac{1}{12} \text{ fields} \] - Therefore, the total work done in 2 hours is: \[ \text{Total Work in 2 hours} = \frac{1}{8} + \frac{1}{12} \] - To add these fractions, find a common denominator (which is 24): \[ \frac{1}{8} = \frac{3}{24}, \quad \frac{1}{12} = \frac{2}{24} \] \[ \text{Total Work in 2 hours} = \frac{3}{24} + \frac{2}{24} = \frac{5}{24} \text{ fields} \] 3. **Determine How Many Cycles Are Needed to Complete the Work:** - The total work required is 1 field. The number of 2-hour cycles needed to complete the work is: \[ \text{Number of Cycles} = \frac{1 \text{ field}}{\frac{5}{24} \text{ fields per 2 hours}} = \frac{24}{5} \text{ cycles} \approx 4.8 \text{ cycles} \] - This means they will complete 4 full cycles (8 hours) and then have some work left. 4. **Calculate Work Done in 4 Full Cycles (8 Hours):** - In 4 cycles (8 hours), the total work done is: \[ \text{Work done in 8 hours} = 4 \times \frac{5}{24} = \frac{20}{24} = \frac{5}{6} \text{ fields} \] 5. **Calculate Remaining Work:** - After 8 hours, the remaining work is: \[ \text{Remaining Work} = 1 - \frac{5}{6} = \frac{1}{6} \text{ fields} \] 6. **Determine Who Works Next:** - After 8 hours (which ends at 5 p.m.), Ganga will work for the next hour (from 5 p.m. to 6 p.m.): - In this hour, Ganga will complete: \[ \text{Work done by Ganga} = \frac{1}{8} \text{ fields} \] - Since \(\frac{1}{8} > \frac{1}{6}\), she will finish the remaining work in less than an hour. 7. **Calculate Time to Complete Remaining Work:** - To find the exact time taken to complete the remaining \(\frac{1}{6}\) fields: \[ \text{Time} = \frac{\text{Remaining Work}}{\text{Work Rate of Ganga}} = \frac{\frac{1}{6}}{\frac{1}{8}} = \frac{8}{6} = \frac{4}{3} \text{ hours} \approx 1 \text{ hour and } 20 \text{ minutes} \] 8. **Final Completion Time:** - Starting from 5 p.m., if Ganga works for \(\frac{4}{3}\) hours, she will finish at: \[ 5 \text{ p.m.} + 1 \text{ hour and } 20 \text{ minutes} = 6:20 \text{ p.m.} \] ### Conclusion: The work will be completed at **6:20 p.m.**.
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