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ABC is a an equilateral triangle of side...

ABC is a an equilateral triangle of side 2 cm . With A , B , C as centres and radius 1 cm three arcs are drawn . The area of the region within the triangle bounded by the three arcs is

A

`(3 sqrt3 - (pi)/(2)) cm^(2)`

B

`(sqrt3 - (3pi)/(2) ) cm^(2)`

C

`(sqrt3 - (pi)/(2))cm^(2)`

D

`((pi)/(2) - sqrt3 ) cm^(2)`

Text Solution

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The correct Answer is:
To find the area of the region within the equilateral triangle ABC bounded by the three arcs, we can follow these steps: ### Step 1: Understand the Triangle Given that ABC is an equilateral triangle with each side measuring 2 cm, we can denote the vertices as A, B, and C. ### Step 2: Calculate the Area of the Triangle The formula for the area of an equilateral triangle is: \[ \text{Area} = \frac{\sqrt{3}}{4} \times \text{side}^2 \] Substituting the side length (2 cm): \[ \text{Area} = \frac{\sqrt{3}}{4} \times (2)^2 = \frac{\sqrt{3}}{4} \times 4 = \sqrt{3} \text{ cm}^2 \] ### Step 3: Determine the Radius and Angle for the Arcs Each arc is drawn with centers at A, B, and C, and has a radius of 1 cm. The angle subtended by each arc at the center of the triangle is 60 degrees (since the triangle is equilateral). ### Step 4: Calculate the Area of One Arc The area of a sector of a circle is given by: \[ \text{Area of sector} = \frac{\theta}{360} \times \pi r^2 \] For one arc: - \(\theta = 60\) degrees - \(r = 1\) cm So the area of one arc is: \[ \text{Area of one arc} = \frac{60}{360} \times \pi \times (1)^2 = \frac{1}{6} \pi \text{ cm}^2 \] ### Step 5: Calculate the Total Area of the Three Arcs Since there are three arcs, the total area of the arcs is: \[ \text{Total area of arcs} = 3 \times \frac{1}{6} \pi = \frac{1}{2} \pi \text{ cm}^2 \] ### Step 6: Find the Area Bounded by the Arcs To find the area within the triangle that is bounded by the arcs, we subtract the area of the arcs from the area of the triangle: \[ \text{Required Area} = \text{Area of triangle} - \text{Total area of arcs} \] Substituting the values: \[ \text{Required Area} = \sqrt{3} - \frac{1}{2} \pi \text{ cm}^2 \] ### Final Answer The area of the region within the triangle bounded by the three arcs is: \[ \sqrt{3} - \frac{1}{2} \pi \text{ cm}^2 \]
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