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A number when divided by 119 leaves rema...

A number when divided by 119 leaves remained 19 . If the same number is divided by 17 , the remainder will be

A

12

B

10

C

7

D

2

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to find the remainder when a number that leaves a remainder of 19 when divided by 119 is divided by 17. ### Step 1: Understand the problem We know that when a number \( N \) is divided by 119, it leaves a remainder of 19. This can be expressed mathematically as: \[ N = 119k + 19 \] where \( k \) is some integer (the quotient). ### Step 2: Substitute values To find the remainder when \( N \) is divided by 17, we can substitute the expression for \( N \): \[ N = 119k + 19 \] ### Step 3: Find \( N \mod 17 \) We need to calculate \( N \mod 17 \): \[ N \mod 17 = (119k + 19) \mod 17 \] ### Step 4: Calculate \( 119 \mod 17 \) First, we need to find \( 119 \mod 17 \): \[ 119 \div 17 = 7 \quad \text{(since } 17 \times 7 = 119\text{)} \] Thus, \[ 119 \mod 17 = 0 \] ### Step 5: Calculate \( 19 \mod 17 \) Now we calculate \( 19 \mod 17 \): \[ 19 \div 17 = 1 \quad \text{(since } 17 \times 1 = 17\text{)} \] Thus, \[ 19 \mod 17 = 2 \] ### Step 6: Combine results Now we can substitute back into our equation: \[ N \mod 17 = (119k \mod 17 + 19 \mod 17) \] Since \( 119k \mod 17 = 0 \): \[ N \mod 17 = 0 + 2 = 2 \] ### Conclusion Therefore, when the number \( N \) is divided by 17, the remainder is **2**.
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