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The bowling average of a cricketer was 1...

The bowling average of a cricketer was 12.4. He decreases his average by 0.2 points when he takes 5 wickets for 26 runs in his last match . The number of wickets taken by him before the last match was

A

125

B

150

C

175

D

200

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the number of wickets taken by the cricketer before his last match, given that his bowling average decreased after taking 5 wickets for 26 runs. ### Step-by-Step Solution: 1. **Understand the Given Information:** - Initial bowling average = 12.4 - Decrease in average = 0.2 - Wickets taken in the last match = 5 - Runs given in the last match = 26 2. **Calculate the New Bowling Average:** - New bowling average after the last match = 12.4 - 0.2 = 12.2 3. **Let the Number of Wickets Before the Last Match be \( p \):** - Total wickets after the last match = \( p + 5 \) - Total runs given before the last match = \( 12.4 \times p \) (since average = total runs / total wickets) 4. **Calculate Total Runs After the Last Match:** - Total runs after the last match = Total runs before last match + Runs in last match - Total runs after the last match = \( 12.4p + 26 \) 5. **Set Up the Equation Using the New Average:** - The new average can be expressed as: \[ \frac{12.4p + 26}{p + 5} = 12.2 \] 6. **Cross-Multiply to Eliminate the Fraction:** \[ 12.4p + 26 = 12.2(p + 5) \] 7. **Expand the Right Side:** \[ 12.4p + 26 = 12.2p + 61 \] 8. **Rearrange the Equation:** - Move all terms involving \( p \) to one side and constant terms to the other side: \[ 12.4p - 12.2p = 61 - 26 \] \[ 0.2p = 35 \] 9. **Solve for \( p \):** \[ p = \frac{35}{0.2} = 175 \] 10. **Conclusion:** - The number of wickets taken by the cricketer before the last match is \( p = 175 \). ### Final Answer: The number of wickets taken by him before the last match was **175**.
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