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By walking at 3/4 of his usual speed, a ...

By walking at `3/4` of his usual speed, a man reaches his office 20 minutes later than his usual time. The usual time taken by him to reach his office is

A

75 minutes

B

60 minutes

C

40 minutes

D

30 minutes

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will denote the usual time taken by the man to reach his office as \( x \) minutes. ### Step 1: Understand the relationship between speed and time When the man walks at \( \frac{3}{4} \) of his usual speed, the time taken to reach his office increases. The relationship between speed and time is inversely proportional; thus, if speed decreases, time increases. ### Step 2: Express the new time taken If the man's usual speed is \( S \), then his usual time taken to reach the office is \( x \) minutes. When he walks at \( \frac{3}{4} S \), the time taken becomes: \[ \text{New time} = \frac{\text{Usual time}}{\text{Fraction of speed}} = \frac{x}{\frac{3}{4}} = \frac{4x}{3} \] ### Step 3: Set up the equation based on the problem statement According to the problem, the man reaches his office 20 minutes later than usual when walking at \( \frac{3}{4} S \). Therefore, we can set up the equation: \[ \frac{4x}{3} - x = 20 \] ### Step 4: Simplify the equation To simplify the left side: \[ \frac{4x}{3} - \frac{3x}{3} = \frac{4x - 3x}{3} = \frac{x}{3} \] So, the equation becomes: \[ \frac{x}{3} = 20 \] ### Step 5: Solve for \( x \) To find \( x \), multiply both sides by 3: \[ x = 20 \times 3 = 60 \] ### Conclusion The usual time taken by the man to reach his office is \( 60 \) minutes.
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