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A is 50% as efficient as B. C does half ...

A is 50% as efficient as B. C does half of the work done by A and B together. If C alone does the work in 20 days, then A, B and C together can do the work in

A

`5(2)/(3)` days

B

`6(2)/(3) ` days

C

6 days

D

7 days

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, let's break it down: ### Step 1: Define the efficiency of A and B Let B's efficiency be represented as 1 unit of work per day. Since A is 50% as efficient as B, A's efficiency will be: \[ \text{Efficiency of A} = 0.5 \times \text{Efficiency of B} = 0.5 \times 1 = 0.5 \text{ units of work per day} \] ### Step 2: Calculate the combined efficiency of A and B The combined efficiency of A and B together is: \[ \text{Efficiency of A + B} = \text{Efficiency of A} + \text{Efficiency of B} = 0.5 + 1 = 1.5 \text{ units of work per day} \] ### Step 3: Determine C's efficiency According to the problem, C does half of the work done by A and B together. Therefore, C's efficiency is: \[ \text{Efficiency of C} = \frac{1}{2} \times \text{Efficiency of (A + B)} = \frac{1}{2} \times 1.5 = 0.75 \text{ units of work per day} \] ### Step 4: Calculate the total work done by C in 20 days If C alone can complete the work in 20 days, the total work can be expressed as: \[ \text{Total Work} = \text{Efficiency of C} \times \text{Time taken by C} = 0.75 \times 20 = 15 \text{ units of work} \] ### Step 5: Calculate the total efficiency of A, B, and C together Now, we need to find the combined efficiency of A, B, and C: \[ \text{Efficiency of (A + B + C)} = \text{Efficiency of A} + \text{Efficiency of B} + \text{Efficiency of C} = 0.5 + 1 + 0.75 = 2.25 \text{ units of work per day} \] ### Step 6: Calculate the time taken by A, B, and C together to complete the work To find out how many days it will take for A, B, and C to complete the total work of 15 units, we use the formula: \[ \text{Time} = \frac{\text{Total Work}}{\text{Combined Efficiency}} = \frac{15}{2.25} \] Calculating this gives: \[ \text{Time} = \frac{15}{2.25} = \frac{15 \times 100}{225} = \frac{1500}{225} = \frac{60}{9} = \frac{20}{3} \text{ days} \] ### Final Answer Thus, A, B, and C together can complete the work in: \[ \frac{20}{3} \text{ days} \text{ or } 6 \frac{2}{3} \text{ days} \]
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