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Walking at (3)/(4) of his usual speed,a...

Walking at `(3)/(4)` of his usual speed,a man is `1(1)/(2)` hours late. His usual time to cover the same distance, in hours, is

A

`4(1)/(2) `

B

`4`

C

`5(1)/(2)`

D

5

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, let's break it down step by step. ### Step 1: Understand the relationship between speed, time, and distance We know that speed and time are inversely proportional when the distance is constant. This means that if speed decreases, time increases. ### Step 2: Define the variables Let the usual speed of the man be \( S \) (in hours). When he walks at \( \frac{3}{4} \) of his usual speed, his new speed becomes \( \frac{3}{4}S \). ### Step 3: Set up the time equations Let the usual time taken to cover the distance be \( T \) (in hours). The time taken at the reduced speed is given by the formula: \[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \] Since the distance remains constant, we can express the time taken at the reduced speed as: \[ \text{Time at reduced speed} = \frac{D}{\frac{3}{4}S} = \frac{4D}{3S} \] And the usual time is: \[ \text{Usual time} = \frac{D}{S} = \frac{D}{S} \] ### Step 4: Relate the times According to the problem, the man is \( 1 \frac{1}{2} \) hours late when walking at \( \frac{3}{4} \) of his speed. This means: \[ \text{Time at reduced speed} - \text{Usual time} = 1 \frac{1}{2} \text{ hours} \] In terms of \( T \): \[ \frac{4D}{3S} - T = \frac{3}{2} \] ### Step 5: Substitute the usual time Since \( T = \frac{D}{S} \), we can substitute this into the equation: \[ \frac{4D}{3S} - \frac{D}{S} = \frac{3}{2} \] ### Step 6: Simplify the equation To simplify, find a common denominator: \[ \frac{4D - 3D}{3S} = \frac{3}{2} \] This simplifies to: \[ \frac{D}{3S} = \frac{3}{2} \] ### Step 7: Cross-multiply to solve for D Cross-multiplying gives: \[ 2D = 9S \] Thus, we can express \( D \) in terms of \( S \): \[ D = \frac{9S}{2} \] ### Step 8: Find the usual time Now, substitute \( D \) back into the equation for usual time: \[ T = \frac{D}{S} = \frac{\frac{9S}{2}}{S} = \frac{9}{2} \text{ hours} \] ### Step 9: Convert to mixed fraction To convert \( \frac{9}{2} \) into a mixed fraction: \[ \frac{9}{2} = 4 \frac{1}{2} \text{ hours} \] ### Final Answer The usual time to cover the same distance is \( 4 \frac{1}{2} \) hours. ---
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