Home
Class 14
MATHS
The difference between the compound inte...

The difference between the compound interest and simple interest for the amount Rs. 5,000 in 2 years is Rs.32. The rate of interest is

A

`5%`

B

`8%`

C

`10%`

D

`12%`

Text Solution

AI Generated Solution

The correct Answer is:
To find the rate of interest given that the difference between the compound interest (CI) and simple interest (SI) for an amount of Rs. 5,000 in 2 years is Rs. 32, we can follow these steps: ### Step 1: Understand the formulas The formulas for compound interest and simple interest are: - Simple Interest (SI) = \( P \times \frac{R \times T}{100} \) - Compound Interest (CI) = \( P \left(1 + \frac{R}{100}\right)^T - P \) Where: - \( P \) = Principal amount (Rs. 5,000) - \( R \) = Rate of interest (unknown) - \( T \) = Time (2 years) ### Step 2: Set up the equation The difference between CI and SI is given as Rs. 32. Therefore, we can write: \[ CI - SI = 32 \] Substituting the formulas: \[ P \left(1 + \frac{R}{100}\right)^T - P - \left(P \times \frac{R \times T}{100}\right) = 32 \] ### Step 3: Substitute the known values Substituting \( P = 5000 \) and \( T = 2 \): \[ 5000 \left(1 + \frac{R}{100}\right)^2 - 5000 - \left(5000 \times \frac{R \times 2}{100}\right) = 32 \] ### Step 4: Simplify the equation First, simplify the left-hand side: \[ 5000 \left(1 + \frac{R}{100}\right)^2 - 5000 - \frac{10000R}{100} = 32 \] \[ 5000 \left(1 + \frac{R}{100}\right)^2 - 5000 - 100R = 32 \] ### Step 5: Factor out 5000 Now, factor out 5000: \[ 5000 \left(\left(1 + \frac{R}{100}\right)^2 - 1 - \frac{2R}{100}\right) = 32 \] ### Step 6: Divide by 5000 Divide both sides by 5000: \[ \left(1 + \frac{R}{100}\right)^2 - 1 - \frac{2R}{100} = \frac{32}{5000} \] \[ \left(1 + \frac{R}{100}\right)^2 - 1 - \frac{2R}{100} = 0.0064 \] ### Step 7: Expand the left-hand side Now, expand the left-hand side: \[ \left(1 + \frac{R}{100}\right)^2 = 1 + 2 \cdot \frac{R}{100} + \left(\frac{R}{100}\right)^2 \] Thus, \[ 1 + 2 \cdot \frac{R}{100} + \left(\frac{R}{100}\right)^2 - 1 - \frac{2R}{100} = 0.0064 \] This simplifies to: \[ \left(\frac{R}{100}\right)^2 = 0.0064 \] ### Step 8: Solve for R Taking the square root of both sides: \[ \frac{R}{100} = 0.08 \] Thus, \[ R = 0.08 \times 100 = 8 \] ### Conclusion The rate of interest is **8%**.
Promotional Banner

Similar Questions

Explore conceptually related problems

The difference between the compound interest and simple interest on Rs. 10,000 for 2 years is Rs.25. The rate of interest per annum is

The difference between compound interest and simple interest at the same rate on Rs 5000 for 2 years is Rs 72 .The rate of interest per annum is

The difference between the compound interest and simple interest on a certain sum at 5% for 2 years is Rs. 1.50 the sum is

The difference between the compound interest and the simple interest accrued on an amount of Rs18,000 in 2 years was Rs 405. What was the rate of interest p.c.p.a.?

The difference between compound interest and simple interest on Rs. 10000 for 3 years at 5% per annum is :

What is the principal amount on which the difference between the compound interest and simple interest is Rs.40 ,after two years at the rate of annual interest 5%?