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root(3)(1 - 127/343) is equal to...

`root(3)(1 - 127/343)` is equal to

A

`5/9`

B

`1 -1/7`

C

`4/7`

D

`1 - 2/7`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( \sqrt[3]{1 - \frac{127}{343}} \), we can follow these steps: ### Step 1: Find a common denominator We need to combine the terms inside the cube root. The denominator of the fraction is 343. We can rewrite 1 as \( \frac{343}{343} \) to have a common denominator. \[ 1 - \frac{127}{343} = \frac{343}{343} - \frac{127}{343} \] ### Step 2: Subtract the fractions Now that we have a common denominator, we can subtract the fractions: \[ \frac{343 - 127}{343} = \frac{216}{343} \] ### Step 3: Substitute back into the cube root Now we can substitute this result back into the cube root: \[ \sqrt[3]{1 - \frac{127}{343}} = \sqrt[3]{\frac{216}{343}} \] ### Step 4: Simplify the cube root We can separate the cube root of the numerator and the denominator: \[ \sqrt[3]{\frac{216}{343}} = \frac{\sqrt[3]{216}}{\sqrt[3]{343}} \] ### Step 5: Calculate the cube roots Next, we need to calculate the cube roots. We know that: - \( 216 = 6^3 \), so \( \sqrt[3]{216} = 6 \) - \( 343 = 7^3 \), so \( \sqrt[3]{343} = 7 \) Thus, we have: \[ \frac{\sqrt[3]{216}}{\sqrt[3]{343}} = \frac{6}{7} \] ### Step 6: Final result Therefore, the final result is: \[ \sqrt[3]{1 - \frac{127}{343}} = \frac{6}{7} \] ### Summary The expression \( \sqrt[3]{1 - \frac{127}{343}} \) simplifies to \( \frac{6}{7} \). ---
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